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If the standed electrode potential for a...

If the standed electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction
`Zn(s)+Cu^(2+)(aq) hArrZn^(2+)(aq)+Cu(s)`
at 300 K is approximately
`(R=8JK^(-1)mol^(-1),F=96000Cmol^(-1))`

A

`e^(160)`

B

`e^(320)`

C

`e^(-160)`

D

`e^(-80)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta G^(@) = - RT ln K = - n FE_(cell)^(@)`
`therefore ln K = (n F E_(cell)^(@))/(RT)`
`= (2 xx 96500 xx 2)/(8 xx 300) = 160`
`therefore K = e^(160)`
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