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Consider the following cell reaction: 2F...

Consider the following cell reaction: `2Fe(s)+O_(2) (g) + 4H^(+)(aq)to2Fe^(2+)(aq)+2H_(2)O(l)`, `E^(@) = 1.67V`
At `[Fe^(2+)] = 10^(-3)M,P_(O_2)=0.1` atm and PH=3 . The cell potential at `25^(@) C`:

A

`1.47 V`

B

`1.77` V

C

`1.87` V

D

`1.57` V

Text Solution

Verified by Experts

The correct Answer is:
D
`E = E^(@) - (0.059)/(4) "log" ([Fe^(2+) ]^(2))/(pO_(2) xx [H^(+)]^(4))`
`= 1.67 - (0.059)/(4) "log" ((10^(-3))^(2))/(0.1 xx (10^(-3))^(4))`
`= 1.67 - (0.059)/(4) "log" 10^(7)`
`= 1.67 - 0.10 = 1.57`
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