In an electrolysis of acidulated water, 4.48 L of hydrogen at STP was produced by passing a current of 2.14 A. For how many hours was the current passed ?

Answer

5

Explanation

`2H^(+) + 2e^(-) to H_(2)`
22.4 L of `H_2` is produced by `= 2 xx 96500 C`
4.48 L of `H_2` is produced by `= (2 xx 96500 xx 4.48)/(22.4)`
`= 38600 C `
Now `38600 C = 2.14 A xx t (s)`
`t = (38600)/(2.14) = 18037 s`
`or t = (18037)/(3600) = 5` hr .