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Given: a+ib=2-3i, find 'a' and 'b'....

Given: `a+ib=2-3i`, find 'a' and 'b'.

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To solve the problem where \( a + ib = 2 - 3i \), we need to find the values of \( a \) and \( b \). ### Step-by-Step Solution: 1. **Identify the given complex number**: We have \( a + ib = 2 - 3i \). 2. **Separate the real and imaginary parts**: In the expression \( a + ib \): - The real part is \( a \). - The imaginary part is \( b \). In the expression \( 2 - 3i \): - The real part is \( 2 \). - The imaginary part is \( -3 \). 3. **Set up equations based on the equality of real and imaginary parts**: Since the two complex numbers are equal, we can equate their real parts and their imaginary parts: - From the real parts: \( a = 2 \) - From the imaginary parts: \( b = -3 \) 4. **Write the final values**: Therefore, we have: - \( a = 2 \) - \( b = -3 \) ### Final Answer: - \( a = 2 \) - \( b = -3 \)
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