Find 'x' and 'y' when:
`(2y+7)+(4-3x)i=0`.

Answer

To find the values of \( x \) and \( y \) in the equation \( (2y + 7) + (4 - 3x)i = 0 \), we will separate the real and imaginary parts and set them equal to zero.

### Step-by-Step Solution:

1. **Identify the real and imaginary parts:**
The equation can be expressed as:
\[ (2y + 7) + (4 - 3x)i = 0 + 0i \]
Here, the real part is \( 2y + 7 \) and the imaginary part is \( 4 - 3x \).

2. **Set the real part equal to zero:**
\[ 2y + 7 = 0 \]

3. **Solve for \( y \):**
\[ 2y = -7 \\ y = -\frac{7}{2} \]

4. **Set the imaginary part equal to zero:**
\[ 4 - 3x = 0 \]

5. **Solve for \( x \):**
\[ -3x = -4 \\ 3x = 4 \\ x = \frac{4}{3} \]

### Final Values:
- \( x = \frac{4}{3} \)
- \( y = -\frac{7}{2} \)