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Find the square roots of -48-14i....

Find the square roots of `-48-14i`.

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To find the square roots of the complex number \(-48 - 14i\), we can follow these steps: ### Step 1: Assume the square root Let \( z = a + bi \), where \( a \) and \( b \) are real numbers. We want to find \( z \) such that: \[ z^2 = -48 - 14i \] ### Step 2: Expand the square Expanding \( z^2 \): \[ (a + bi)^2 = a^2 + 2abi + (bi)^2 = a^2 + 2abi - b^2 \] This can be rewritten as: \[ (a^2 - b^2) + (2ab)i \] ### Step 3: Set real and imaginary parts equal From the equation \( z^2 = -48 - 14i \), we can equate the real and imaginary parts: 1. \( a^2 - b^2 = -48 \) (1) 2. \( 2ab = -14 \) (2) ### Step 4: Solve for \( b \) in terms of \( a \) From equation (2): \[ b = \frac{-14}{2a} = \frac{-7}{a} \] ### Step 5: Substitute \( b \) into equation (1) Substituting \( b \) into equation (1): \[ a^2 - \left(\frac{-7}{a}\right)^2 = -48 \] This simplifies to: \[ a^2 - \frac{49}{a^2} = -48 \] ### Step 6: Multiply through by \( a^2 \) To eliminate the fraction, multiply through by \( a^2 \): \[ a^4 + 48a^2 - 49 = 0 \] ### Step 7: Let \( x = a^2 \) Let \( x = a^2 \). The equation becomes: \[ x^2 + 48x - 49 = 0 \] ### Step 8: Use the quadratic formula Using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): \[ x = \frac{-48 \pm \sqrt{48^2 + 4 \cdot 49}}{2} \] Calculating the discriminant: \[ 48^2 = 2304, \quad 4 \cdot 49 = 196 \quad \Rightarrow \quad 2304 + 196 = 2500 \] Thus, \[ x = \frac{-48 \pm 50}{2} \] ### Step 9: Solve for \( x \) Calculating the two possible values: 1. \( x = \frac{2}{2} = 1 \) 2. \( x = \frac{-98}{2} = -49 \) (not possible since \( x = a^2 \) must be non-negative) ### Step 10: Find \( a \) and \( b \) Since \( x = a^2 = 1 \): \[ a = \pm 1 \] Substituting \( a \) back to find \( b \): \[ b = \frac{-7}{a} \quad \Rightarrow \quad b = -7 \text{ (if } a = 1\text{) or } b = 7 \text{ (if } a = -1\text{)} \] ### Step 11: Write the final answers Thus, the square roots of \(-48 - 14i\) are: \[ z = 1 - 7i \quad \text{and} \quad z = -1 + 7i \] So we can express the final answer as: \[ \sqrt{-48 - 14i} = \pm (1 - 7i) \]
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