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Position of a body with acceleration a i...

Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.

A

m= 1, n=1

B

m=1,n=2

C

m=2, n=1

D

m=2, n=2

Text Solution

Verified by Experts

The correct Answer is:
B
`x=Ka^(m)t^(n)`
`[M^(0)LT^(0)]=[M^(0)L^(m)T^(-2m)][M^(0)L^(0)T^(n)]`
`[M^(0)LT^(0)]=[M^(0)L^(m)T^(n-2m)]`
Both side dimensions should be equal.
`:.m=1`
` n-2m=0,n=2m=2`.
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