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The length of a strip measured with a me...

The length of a strip measured with a meter rod is 10.0cm. Its width measured with a venier calipers is 1.00cm. The least count of the meter rod is 0.1 cm and that of vernier calipers 0.01cm. What will be error in its area?

A

`pm0.01cm^(2)`

B

`pm0.1cm^(2)`

C

`pm0.11cm^(2)`

D

`pm0.2cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaA=((Deltal)/(l)+(DeltaW)/(W))xxA`
`=[(0.1)/(10.0)+(0.01)/(1.00)]xx(10.0xx1.00)cm^(2)=0.20cm^(2)`
`:.DeltaA=pm0.2cm^(2)`
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