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If E = energy , G= gravitational constan...

If `E` = energy , `G`= gravitational constant, `I`=impulse and `M`=mass, then dimensions of `(GIM^(2))/(E^(2)` are same as that of

A

time

B

mass

C

length

D

force.

Text Solution

Verified by Experts

The correct Answer is:
A
`E=[ML^(2)T^(-2)],G=[M^(-1)L^(3)T^(-2)],I=[MLT^(-1)]`
`:.(GIM^(2))/(E^(2))=([M^(-1)L^(3)T^(-2)][MLT^(-1)][M^(2)])/([ML^(2)T^(-2)]^(2))=[T]`.
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