Home
Class 12
PHYSICS
If the ratio of the intensity of two coh...

If the ratio of the intensity of two coherent sources is 4 then the visibility `[(I_(max)-I_(min))//(I_(max)+I_(min))]` of the fringes is

A

4

B

`4//5`

C

`3//5`

D

9

Text Solution

Verified by Experts

The correct Answer is:
B
`(I_(max)-I_("min"))/(I_(max)+I_("min"))=((sqrt(I_(1))+sqrt(I_(2)))^(2)-(sqrt(I_(1))-sqrt(I_(2)))^(2))/((sqrt(I_(1))+sqrt(I_(2)))^(2)+(sqrt(I_(1))-sqrt(I_(2)))^(2))`
`=((1+2)^(2)-(1-2)^(2))/((1+2)^(2)+(1-2)^(2))=(8)/(10)=(4)/(5)`.
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTION (MCQ.s)|9 Videos

  • THERMODYNAMICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions|12 Videos

  • WORK, POWER, ENERGY

    MTG-WBJEE|Exercise EXERCISE (WB JEE Previous Years Questions) CATEGORY 1 : Single Option Correct Type (1 Mark)|3 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources of intensity ratio beta interfere, then (I_(max)-I_(min))/(I_(max)+I_(min)) is

Two coherent sources of intensity ratio beta^2 interfere. Then, the value of (I_(max)- I_(min))//(I_(max)+I_(min)) is

Two doherent sources of intensity ratio alpha interfere in interference pattern (I_(max)-I_(min))/(I_(max)+I_(min)) is equal to

Two coherent sources with intensity ratio alpha interfere. Then, the ratio (l_(max)-l_("min"))/(l_(max)+l_("min")) is

Two coherent sources of intensity ratio alpha interfere. In interference pattern (I_(max)-I_("min"))/(I_(max)-I_("min")) =

The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference patten, the ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be

Two coherent light sources having intensity in the ratio 2x produce an interference pattern. The ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be :

The intensity ratio of the two interfering beams of light is m. What is the value of I_("max")-I_("min") // I_("max")+I_("min") ?