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A single slit Fraunhoffer diffraction pa...

A single slit Fraunhoffer diffraction patternn is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the patternn of red light of wavelength 6300 Å?

A

4400 Å

B

4100 Å

C

4642.8 Å

D

9100 Å

Text Solution

Verified by Experts

The correct Answer is:
C
`x=((2n+1)lamdaD)/(2a)`
For red light, `x=((4+1)D)/(2a)xx6500` Å . . (i)
for other light, `x=((6+1)D)/(2a)xxlamda` Å . . (ii)
x is same for each.
Equating eqn (i) and (ii), we get
`5xx6500=7xxlamda implies lamda=(5)/(7)xx6500=4642.8` Å
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