If `g_E` and `g_M` are the acceleration due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio
electronic charge on the moon/electronic charge on the earth to be

Options

A. `gM/gE`
B. 1
C. 0
D. `gE/gM`

Answer

B

Explanation

Since electrons charge `(1.6 xx 10^(-19)C)` is universal constant. It does not depend on g.
`therefore` Electronic charge on the Moon = electronic charge on the Earth
or `("electronic charge on the Moon")/("electronic charge on the Earth")=1`