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In an experiment on photoelectric effect...

In an experiment on photoelectric effect, a student plots stopping potential `V_(0)` against reciprocal of the wavelength `lamda` of the incident light for two different metals A and B. These are shown in the figure

Looking at the graphs, you can most appropriately say that :

A

`V_2 lt V_1`

B

`V_1 lt V_2 lt 2V_1`

C

`V_2 = 2V_1`

D

`V_2 gt 2V_1`

Text Solution

Verified by Experts

The correct Answer is:
D
According to Einstein.s photoelectric equation
`rArr V_(0) = (hc)/(lambda_e) - (phi_0)/(e) rArr V_1 = (hc)/(lambda_e) - (phi_0)/(e)`
`V_(2) = (hc)/((lambda/2)e)-(phi_0)/(e)=(2hc)/(lambdae)-(phi0)/(e)=2((hc)/(lambda_e)-(phi0)/(e))+(phi0)/(e)`
`V_2 =2V_1 + phi_0//e therefore V_2 gt 2V_1`
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