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The photoelectric threshold wavelength f...

The photoelectric threshold wavelength for silver is `lamda_(0)`. The energy of the electron ejected from the surface of silver by an incident wavelength `lamda(lamdaltlamda_(0))` will be

A

`hc(lambda_(0) - lambda_(0))`

B

`(hc)/(lambda_0-lambda)`

C

`(h)/(c) ((lambda_0-lambda)/(lambda lambda_0))`

D

`hc((lambda_0 -lambda)/(lambda lambda_0))`

Text Solution

Verified by Experts

The correct Answer is:
D
According to Einsteirn photoelectric equation
`K = (hc)/(lambda)-(hc)/(lambda_0)=hc((1)/(lambda)-(1)/(lambda_0))=hc((lambda_0-lambda)/(lambdalambda_0))`
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