After absorbing a slowly moving neutrons of mass `m_(N)` (momentum ~0) a nucleus of mass M breaks into two nucleii of mass `m_(1) and 5m_(1)(6m_(1)=M+m_(N))`, respectively . If the de-Broglie wavelength of the nucleus with mass `m_(1) ` is ` lambda`, then de Broglie wavelength of the other nucleus will be

Options

A. `5 lambda`
B. `lambda//5`
C. `lambda`
D. `25 lambda`

Answer

C

Explanation

`P_i=0 " and " pf=p_1 +p_2`
As pi =pf,, So, 0= `p_1 +p_2 or p_1`
Now `lambda_1 = (h)/(p_1)` and `lambda_2 = (h)/(p_2)`
So, `lambda_1 - lambda_2 =lambda`