An electron of mass `m` and charge `e` initially at rest gets accelerated by a constant electric field `E`. The rate of change of de-Broglie wavelength of this electron at time `t` ignoring relativistic effects is

Options

A. `-(h)/(eEt^2)`
B. `-(2h)/(eEt^2)`
C. `-(3h)/(eEt^2)`
D. `-(4h)/(eEt^2)`

Answer

A

Explanation

`lambda` de -broglie `=(h)/(sqrt(2mK)) = (h)/(mv)`
`v-u + at =0 +((eE)/(m)) t rArr lambda = (h)/(eEt)^2`