A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal to

Options

A. 1
B. 1.1
C. 1.04
D. 0.98

Answer

A

Explanation

Powre of source `= E/t = (nhupsilon)/(t) = Nh upsilon = (Nhc)/(lambda)` where N= number of photons emitted per second
`therefore (P_2)/(P_1) = (N_2hc)/(lambda_2) xx (lambda_1)/(N_1hc)`
`= (lambda_1N_2)/(N_1 lambda_2)= (5000 xx 10^(-10)xx1.02 xx 10^(15))/(10^15 xx 5100 xx 10^(-10))=(50 xx 1.02)/(51)=1`