There are `N_(1)` photons of frequency `v_(1)`, in a beam of light, In another light beam of equal energy there are `N_(2)` photons of frequency `v_(2)`. Then `N_(1)` and `N_(2)` are related as

Options

A. `(N_1)/(N_2)=1`
B. `(N_1)/(N_2)=(upsilon_1)/(upsilon_2)`
C. `(N_1)/(N_2)=(upsilon_2)/(upsilon_1)`
D. `(N_1)/(N_2) = sqrt((upsilon_2)/(upsilon_1))`

Answer

C

Explanation

Since they have same energy `E_(1) =E_(2)`
`therefore N_(1)h upsilon_(1) = N_(2) h upsilon_(2) therefore (N_1)/(N_2) = (upsilon_2)/(upsilon_1)`