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An electron accelerated through a potent...

An electron accelerated through a potential of 10,000 V from rest has a de-Broglie wavelength `lambda`. What should be the accelerating potential so that the wavelength is doubled?

A

20,000 V

B

40,000 V

C

5,000 V

D

2,500 V

Text Solution

Verified by Experts

The correct Answer is:
D
The wavelength associated with the moving electron is given by
`lambda = (12.27)/(sqrt(V))` where V = accelerating with the moving eletron is given by
`lambda = (12.27)/(sqrt(V))` where V = accelerating potential
`because lambdaprop (1)/(sqrt(v)) therefore lambda/(lambda.) = sqrt((v.)/(V)) rArr lambda/(2lambda) = sqrt((v.)/(10000))`
`rArr V. = 2500 V`
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