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The total energy of eletcron in the grou...

The total energy of eletcron in the ground state of hydrogen atom is `-13.6 eV`. The kinetic enegry of an electron in the first excited state is

A

6.8 eV

B

13.6 eV

C

1.7 eV

D

3.4 eV

Text Solution

Verified by Experts

The correct Answer is:
D
Energy of `n^(th)` orbit of hydrogen atom is given by,
`E_(n)=(-13.6)/(n^(2))eV`
For ground state, n = 1
`therefore E_(1)=(-13.6)/1^(2)=-13.6 eV`
For first excited state, n = 2
`therefore E_(2)=(-13.6)/2^(2)=-3.4eV`
Kinetic energy of an electron in the first excited state is
`K=-E_(2)=3.4 eV`.
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