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Radius of the first orbit of the electro...

Radius of the first orbit of the electron in a hydrogen atom is `0.53 Å` . So, the radius of the third orbit will be

A

1.12 `overset(@)(A)`

B

4.77 `overset(@)(A)`

C

1.06 `overset(@)(A)`

D

1.59 `overset(@)(A)`

Text Solution

Verified by Experts

The correct Answer is:
B
Radius of stationary orbit = r
`r=I/(4piepsilon_(0))*(Ze^(2))/(mv^(2))=(epsilon_(0)*n^(2)h^(2))/(pimZe^(2))=((epsilon_(0)h^(2))/(pimZe^(2)))*n^(2)`
`therefore r_(3)/r_(1)=3^(2)=9 rArr r_(3)=9r_(1)=9 times 0.53=4.77 overset(@)(A)`
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