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In Rutherford's scattering experiment , ...

In Rutherford's scattering experiment , 60 particles were scattered per min for `theta_1 = 90^@`. How many particles will be scattered per min for `theta_2 = 60^@` ?

A

60

B

120

C

180

D

240

Text Solution

Verified by Experts

The correct Answer is:
D
Given : `theta_(1)=90^(@), N_(1)=60" and "theta_(2)=60^(@)`
In Rutherford.s scattering experiment, the number of scattering particles,
`N propto 1/(sin^(4)(theta/2))`
`therefore N_(2)/N_(1)=[(sin(theta_(1)/2))/(sin(theta_(2)/2))]^(4)=[sin45^(@)/sin30^(@)]^(4)`
`" "=[(1/sqrt(2))/(1/2)]^(4)=[2/sqrt(2)]^(4)=[sqrt(2)]^(4)=4`
`therefore N_(2)=4N_(1)=4 times 60=240`
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