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What is the radius of iodine atom (at no...

What is the radius of iodine atom (at no. `53`, mass number `126`)?

A

`2.5 times 10^(-9)m`

B

`7 times 10^(6)m`

C

`7 times 10^(-9)m`

D

`2.5 times 10^(-11)m`

Text Solution

Verified by Experts

The correct Answer is:
D
The electronic configuration of iodine (Z = 53) is 2, 8, 18, 18, 7
`therefore n=5" and "r_(n)=r_(0)(n^(2)/Z)`
and `because r_(0)=0.53 overset(@)(A)=0.53 times 10^(-10)m`
`therefore r_(n)=0.53 times 10^(-10) times 5^(2)/53=(0.53 times 25)/53 times 10^(-10)`
`" "=25 times 10^(-12)=2.5 times 10^(-11)m`
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