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In Bohr's model of the hydrogen atom:...

In Bohr's model of the hydrogen atom:

A

the radius of the `n^(th)` orbit is proportional to `n^(2)`

B

the total energy of the electron in `n^(th)` orbit is inversely proportional to n.

C

the angular momentum of electron in an `n^(th)` orbit is an integral multiple of `h//2pi`.

D

the magnitude of potential energy of the electron in any orbit is greater than its kinetic energy.

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
As `r_(n) propto n^(2)`. Option (a) is correct.
Total energy of electron `=(-13.6 Z^(2))/n^(2)`
So, option (b) is not correct.
Angular momentum of electron `=nh//2pi`.
So, option (c) is correct.
Potential energy of an electron `=(-27.2//n^(2))` eV for hydrogen atom.
`therefore abs(P.E.)=(27.2)/n^(2)`
Kinetic energy of electron `=13.6//n^(2)`. It is always positive.
`therefore abs(P.E.)=2 times abs(K.E.)`
The option (d) is correct.
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