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The de-Broglie wavelength lambda(n)of th...

The de-Broglie wavelength `lambda_(n)`of the electron in the `n^(th)` orbit of hydrogen atom is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
`2pir_(n)=nlambda`
n = 2, `2pir_(2)=2lambda=2 times` de-Broglie wavelength.
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