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In the nuclear reaction .(7)^(14)N+X to ...

In the nuclear reaction `._(7)^(14)N+X to ._(6)^(14)C+._(1)^(2)H`, the X will be

A

`""_(-1)^(0) e`

B

`""_(1)^(1)H`

C

`""_(1)^(2)H`

D

`""_(0)^(1)n`

Text Solution

Verified by Experts

The correct Answer is:
D
`""_(7)^(14)N + ""_(Z)^(A) X rarr ""_(6)^(14)C + ""_(1)^(1)H`
According to conservation of charge number
7 + Z = 6 + 1 or Z = 0
According to conservation of mass number
14 + A = 14 + 1 or A = 1
Hence, the X will be `""_(0)^(1)n`
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