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If .92 U^238 undergoes successively 8 al...

If `._92 U^238` undergoes successively `8 alpha-`decays and `6 beta-`decays, then resulting nucleus is.

A

`""_(82)U^(208)`

B

`""_(82)Pb^(206)`

C

`""_(82)U^(210)`

D

`""_(82)U^(214)`

Text Solution

Verified by Experts

The correct Answer is:
B
`8 alpha`-decays `= 8 xx (""_(2)He^(4))` = Z decreases by 16 and A decreases by 32.
`6 beta`-decays `rarr 6 (""_(-1)beta^(0))` = Z increases by 6.
`therefore` Change in Z = 16 - 6 = 10 = Decrease in Z
Decrease in A = 32
`therefore` Final A = 238 - 32 = 206
`therefore` Resulting nucleus `= ""_(82)Pb^(206)`
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