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A radioactive substance decays to ((1)/(...

A radioactive substance decays to `((1)/(16))^(th)` of its initial activity in 40 days. The half-life of the radioacctive substance expressed in days is

A

2.5

B

5

C

10

D

20

Text Solution

Verified by Experts

The correct Answer is:
C
`(N)/(N_(0)) = ((1)/(2))^(n) rArr ((1)/(16)) = ((1)/(2))^(n) rArr n = 4`
`therefore` Half life `(T_(1//2)) = (t)/(n) = (40)/(4) = 10` days.
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