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In the final Uranium radioactive series ...

In the final Uranium radioactive series the initial nucleus is `U_(92)^(238) ` and the final nucleus is `Pb_(82)^(206)` . When Uranium neucleus decays to lead , the number of a - particle is …….. And the number of `beta` - particles emited is ……

A

1

B

2

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Number of alpha particles emitted will be,
`n_(alpha) = (A_(1) - A_(2))/(4) = (238 - 206)/(4) = (32)/(4) = 8`
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