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Neutron decay in the free space is given...

Neutron decay in the free space is given follows:
`._0n^1 rarr. _1H^1 +._(-e)^0 +[]`
Then, the parenthesis represents

A

photon

B

graviton

C

neutrino

D

antineutrino

Text Solution

Verified by Experts

The correct Answer is:
D
The emission of antineutrino is must for the validity of different laws.
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