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If M(o) is the mass of an oxygen isotope...

If `M_(o)` is the mass of an oxygen isotope `._(8)O^(17), M_(p)` and `M_(N)` are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

A

`M_(0)C^(2)`

B

`(M_(0) - 8 M_(P))C^(2)`

C

`(M_(0) - 17M_(N))C^(2)`

D

`(M_(0) - 8M_(P) - 9 M_(N))C^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
The isotope `""_(8)O^(17)` contains 8 protons and 9 neutrons.
`therefore` Mass of oxygen isotope nucleus `= 8 M_(P) + 9 M_(N)`
The mass defect of nucleus `(Delta m)`
= mass of nucleus - mass of isotope nucleus
`rArr" "Delta m = M_(0) - 8M_(P) - 9 M_(N)`
`therefore` Binding energy = mass defect `xx c^(2)`
`rArr" "B.E = (M_(0) - 8 M_(P) - 9 M_(N)) c^(2)`
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