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An equilibrium mixture for the reaction ...

An equilibrium mixture for the reaction
`2H_(2)S_((g))iff2H_(2(g))+S_(2(g))` had one mole of hydrogen sulphide, 0.2 mole of `H_(2)` and 0.8 mole of `S_(2)` in a 2 litre vessel. The value of `K_(c )` in mole `"litre"^(-1)` is

A

`0.004`

B

`0.016`

C

`0.080`

D

`0.032`

Text Solution

Verified by Experts

The correct Answer is:
B
`K=((0.2//2)^(2)(0.8//2))/((1//2)^(2))=((0.1)^(2)(0.4))/((0.5)^(2))=0.016`
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