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1 mole of N(2) and 2 moles of H(2) are a...

1 mole of `N_(2)` and 2 moles of `H_(2)` are allowed to react in a `1 dm^(3)` vessel. At equilibrium, 0.8 mole of `NH_(3)` is formed. The concentration of `H_(2)` in the vessel is

A

0.6 mole

B

0.8 mole

C

0.2 mole

D

0.4 mole

Text Solution

Verified by Experts

The correct Answer is:
B
`N_(2)+3H_(2)iff2NH_(3)`
Formation of 0.8 mole of `NH_(3)` means that `(3)/(2)xx0.8` mole of `H_(2)` have reacted.
Hence, concentration of `H_(2)=2-(3)/(2)xx0.8`
`=2-1.2=0.8" mole"`
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