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2 mol of N(2) is mixed with 6 mol of H(2...

2 mol of `N_(2)` is mixed with 6 mol of `H_(2)` in a closed vessel of one litre capacity. If 50% of `N_(2)` is converted into `NH_(3)` at equilibrium, the value of `K_(c)` for the reaction
`N_(2(g))+3H_(2(g))iff2NH_(3(g))` is

A

`4//27`

B

`27//4`

C

`1//27`

D

27

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,N_(2),+,3H_(2),iff,2NH_(3)),("Initial","2 mol",,"6 mol",,),("At. eqm.","1 mol",,"3 mol",,),("Molar conc.",1,,3,,"2 mol ""^(-1) ):}`
`K_(c)=((2)^(2))/(1xx(3)^(3))=(4)/(27)`
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