हल कीजिये:
`5/(2-x) + (x-5)/(x+2) + (3x+8)/(x^(2)-4)=0`

Solve the equation : (5)/(2-x)+(x-5)/(x+2)+(3x+8)/(x^(2)-4)=0

(2x)/(5-3x)=(5+3x)/(8x)

(5-2x) (3x + 4) (x-4)> = 0

If x≠ − 1 , 2 and 5, then the simplified value of {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} is equal to: यदि x≠ − 1 , 2 और 5 है तो {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} का सरलीकृत मान बराबर हैः

If P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) and R=(2x^2+4x+8)/(x-5) , then (PxxQ) div R is equal to: यदि P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) तथा R=(2x^2+4x+8)/(x-5) है, तो (PxxQ) div R का मान किसके बराबर है ?

Check whether the following are quadratic equations : (1) (x-3)^(2)=x(2x-5) (2) (2x-3)(8x+1) = (4x+5)(4x-5) (3) (5x+3)(x-2)=(4x+3)(2x-1) (4) (2x+5)^(3)=8(x-1)^(3) (5) x^(2)+7x-8=x(x+5) (6) x^(3)+9x^(2)-7x+2=(x+3)^(3)

If x ne -1,2 and 5, then the simplified value of {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) is equal to : यदि x ne -1,2 और 5 है, तो {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) का सरलीकृत मान क्या होगा ?

A quadratic equation whose roots are cosec^2theta and sec^2theta can be (1) x^2-2x+ 2 =0 (2) x^2-3x + 3 = 0 (3) x^2-3x+ 4= 0 (4) x^2-5x+5= 0

x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0