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epsi(0)mu(0) का विमिये सूत्र लिखिए!...

`epsi_(0)mu_(0)` का विमिये सूत्र लिखिए!

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Dimension of the quantity (p)/(epsi _(0) mu_(0)), where p is the pressure, epsi _(0) is electric permitivity of face space and mu _(0) is permebility of free space, will be

If epsi_(0) and mu_(0) are respectively, the electric permittivity and the magnetic permeability of free space, epsi and mu the corresponding quantities in a medium, the refractive index of the medium is

In terms of potential difference V, electric current I, permitivity epsi_(0) , permeability mu_(0) and speed of light c, the dimensionally correct equations (s) is (are) :

In terms of potential difference V, electric current I, permitivity epsi_(0) , permeability mu_(0) and speed of light c, the dimensionally correct equations (s) is (are) :

In a electro magnetic wave the expression for electric field is given by E=50 sin (omegat-kx) the permeability is given mu=4mu_(0) & permittivity epsi_(0)=epsi_(r) , then find the average intensity delivered.

In a electro magnetic wave the expression for electric field is given by E=50 sin (omegat-kx) the permeability is given mu=4mu_(0) & permittivity epsi_(0)=epsi_(r) , then find the average intensity delivered.