For a chemical reaction `aArarr bB`,
`log[-(d(A))/(dt)]=log[(d[B])/(dt)]+0.3`
Then find the approximately ratio of `a` and `b` is.

For a chemical reaction aAtoB,log[-(d[A])/(dt)]=log[(d[B])/(dt)]+0.3 then find the approximate ratio and of a and b

In the reaction x A rarr yB, log{-(d[A])/(dt)}=log{+(d[B])/(dt)}+0.3 Then, x:y is

For a chemical reaction xP rarr yQ In [-(d[P])/(dt)] = In[(d[Q])/(dt)]+6.909 The ratio of x to y is approximately 10^n ,n = ?

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) In the following reaction, xA rarr yB log.[-(d[A])/(dt)] = log.[(d[B])/(dt)] + 0.3 where negative isgn indicates rate of disappearance of the reactant. Thus, x:y is:

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) In the following reaction, xA rarr yB log.[-(d[A])/(dt)] = log.[(d[B])/(dt)] + 0.3 where negative isgn indicates rate of disappearance of the reactant. Thus, x:y is:

(d)/(dt)log(1+t^(2))

For the reaction : aA to bB , it is given that log[(-dA)/(dt)] = log [(dB)/(dt)] + 0.6020 . What is a : b is ?

For the reaction : aA to bB , it is given that log[(-dA)/(dt)] = log [(dB)/(dt)] + 0.6020 . What is a : b is ?

In the following reaction, xA rarryB log_(10)[-(d[A])/(dt)]=log_(10)[(d([B]))/(dt)]+0.3010 ‘A’ and ‘B’ respectively can be: