`f'(x)>=g'(x)`, if `f(x)=5-3x+5/2x^2-(x^3)/3,g(x)=3x-7`.

f(x)=9x^(3)-3x^(2)+x-5,g(x)=x-(2)/(3)

divide f(x)=5x^2+3x+1 by g(x)=2x

check whether g(x) is a factor of f(x) or not f(x)=x^5+3x^4−x^3−3x^2+5x+15 , g(x)=x+3

If: f(x)=5-x^2,g(x)=3x-4 , then: (f@g)(-1)=

Find gofa n dfog wehn f: RvecR and g: RvecR are defined by f(x)=2x+3 and g(x)=x^2+5 f(x)=2x+x^2 and g(x)=x^3 f(x)=x^2+8 and g(x)=3x^3+1 f(x)=8x^3 and g(x)=x^(1//3)