In `DeltaABC,(a+b-c)(b+c-a)(c+a-b)-abc` is always

In a DeltaABC,(a+b+c)(b+c-a)=lambdabc , then

In any Delta ABC,((a+b+c)(b+c-a)(c+a-b)(a+b-c))/(4b^2c^2) =

If in DeltaABC, (a+b+c) (b+c-a) = abc , find the condition of a

In DeltaABC, if (a+b+c)(b+c-a)=3bc , then A=

In DeltaABC if (b)/(c+a)+(c)/(a+b)=1 then

If a,b,c in R^(+), then (bc)/(b+c)+(ac)/(a+c)+(ab)/(a+b) is always (a) (a) =(1)/(3)sqrt(abc)(c) =(1)/(2)sqrt(abc)

If a,b,c in R^(+) then b(c)/(b+c)+a(c)/(a+c)+a(b)/(a+b) is always

If a ,b ,c in R^+, t h e n(b c)/(b+c)+(a c)/(a+c)+(a b)/(a+b) is always