For complex numbers `z_1 = 6+3i, z_2=3-I ` find `(z_1)/(z_2)`

Consider the complex number z_1 = 2 - i and z_2 = -2 + i Find (z_1z_2)/z_1 . Hence, find abs((z_1z_2)/z_1)

Consider the complex number z_1 = 2 - i and z_2 = 2 + i Find 1/(z_1z_2) . Hence, prove than I_m(1/(z_1z_2)) = 0

Consider the complex number z_1 = 3+i and z_2 = 1+i .Find 1/z_2

The complex numbers z_1, z_2 and z_3 satisfying (z_1-z_3)/(z_2- z_3)= (1-i sqrt3)/2 are the vertices of triangle, which is :

The complex numbers z_(1), z_(2), z_(3) satisfying (z_(1)-z_(3))/(z_(2)-z_(3))=(1-i sqrt(3))/(2) are the vertices of a triangle which is

If z_1 = 2 -i and z_2= -2+i , find Re((z_1 z_2)/z_1) .

If z_1=2-i ,\ z_2=1+i , find |(z_1+z_2+1)/(z_1-z_2+i)|

For all complex numbers z_1,z_2 satisfying |z_1|=12 and |z_2-3-4i|=5 , find the minimum value of |z_1-z_2|

For all complex numbers z_1,z_2 satisfying |z_1|=12 and |z_2-3-4i|=5 , find the minimum value of |z_1-z_2|

If z_1=3+i,z_2=1-3i , then find barz_1.barz_2