The resistance of 0.05 `MCH_(3)COOH` solution is found to be 100ohm. If the cell constant is 0.037 `cm^(-1)` , the molar conductivity of the solution is

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 cm^(-1) the electrical conductivity of the solution is

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 cm^(-1) the electrical conductivity of the solution is

The resistance of 0.05M KCl solution at 25^@C is 100 ohm in a cell whose cell constant is 0.3765cm^(-1) . The specific conductivity of KCl solution is

In a conductive cell, at 298K, the resistance of 0.05M NaOH solution is 31.16. Ifthe cell constant of that cell is 0.367 cm^(-1) , then calculate molar conductance of the given solution.

In a conductive cell, at 298K, the resistance of 0.05M NaOH solution is 31.16. Ifthe cell constant of that cell is 0.367 cm^(-1) , then calculate molar conductance of the given solution.

0.05 "M" NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm^(_1) calculate the molar conductivity of the NaOH solution.

The resistance of 0.01 MCH_(3)COOH solution is found to be 2220 ohm whne measured in a cell of cell constant 0.366 cm^(-1) Given that lambda_(m)^(@)(H^(+)) and lambda_(m)^(@)(cH_(3)COO^(-)) as 349.1 and 40.9 cm^(2) mol^(-1) calculate

A. 0.05 M NaOH solution offered, a.resistance of 31.6 ohm in a conductivity cell at 298 K. if the cell constant is 0.367 cm^-1.calculate molar conductivity of the sodium hydroxide soIution.