The length of perpendicular from the origin on the line x/a + y/b = 1 is -

If 2p is the length of perpendicular from the origin to the lines x/a+ y/b = 1, then a^2,8p^2,b^2 are in

If p be the length of the perpendicular from the origin on the line x/a+y/b=1 , then

If p is the length of perpendicular from the origin on the line x/a+y/b=1 and a^(2),p^(2),b^(2) are in A.P., then (A) a^(4)+b^(4)=0 (B) a^(4)-b^(4)=0 (C) a^(2)+b^(2)=0 (D) a^(2)-b^(2)=0

If p be the length of the perpendicular from the origin on the line x//a+y//b =1, then p^2=a^2+b^2 b. p^2=1/(a^2)+1/(b^2) c. 1/(p^2)=1/(a^2)+1/(b^2) d. none of these

If p is the length of perpendicular from the origin on the line (x)/(a)+(y)/(b)=1 and a^(2) , p^(2) and b^(2) are in AP, the show that a^(4)+b^(4)=0 .

If p is the length of perpendicular from the origin on the line (x)/(a) + (y)/( b) =1 and a^(2), p^(2) and b^(2) are in A.P., then show that a^(4) + b^(4) =0 .

If p is the length of perpendicular from the origin on the line (x)/(a)+(y)/(b)=1 and a^(2) , p^(2) and b^(2) are in AP, the show that a^(4)+b^(4)=0 .

Select and write the correct answer from the given alternatives in each of the following:The length of perpendicular to the origin from the line is x/a+y/b=1