Calculate the velocity with which a body must be thrown vertically from the surface of the earth so that it may reach a height of `10R`, where `R` is the radus of the earth and is equal to `6.4xx10^(8)m`. (earth's mass`=6xx10^(24)kg`, gravitational constant `G=6.7xx10^(-11)Nm^(2)kg^(-2))`

Calculate the velocity with which a body must be thrown vertically upward from the surface of the earth so that it may reach a height of 10R , where R is the radius of the earth and is equal to 6.4 xx 10^(6)m. (Given: Mass of the earth = 6 xx 10^(24) kg , gravitational constant G = 6.7 xx 10^(-11) N m^(2) kg^(-2) )

Calculate the velocity with which a body must be thrown vertically upward from the surface of the earth so that it may reach a height of 10R , where R is the radius of the earth and is equal to 6.4 xx 10^(6)m. (Given: Mass of the earth = 6 xx 10^(24) kg , gravitational constant G = 6.7 xx 10^(-11) N m^(2) kg^(-2) )

With what velocity must a body be thrown upward form the surface of the earth so that it reaches a height of 10 R_(e) ? earth's mass M_(e) = 6 xx 10^(24) kg , radius R_(e) = 6.4 xx 10^(6) m and G = 6.67 xx 10^(-11) N-m^(2)//kg^(2) .

A body is to be projected vertically upwards from earth's surface to reach a height of 9R , where R is the radius of earth. What is the velocity required to do so? Given g=10ms^(-2) and radius of earth =6.4xx10^(6)m .

Find the escape velocity of a body from the earth. [R(earth) =6.4xx10^(6)m, rho" (earth)"=5.52xx10^(3)kg//m^(3), G=6.67xx10^(-11)N.m^(2)//kg^(2)]

Calculate the gravitational force due to the earth on mahendra who has mass of 75kg. [mass of earth =6xx10^24 kg " Radius of the earth " = 6.4xx10^6m , " Gravitational constant " (G) = 6.67xx10^(-11) Nm^2//kg^2 ]

If mass of Earth is 6xx10^24 kg, radius of Earth is 6.4 xx 10^6m and the gravitational constant is 6.7 xx10^-(11)Nm^2kg(-2) . Calculate the value of g.

What is the gravitational potential due to the Earth at a point which is at a height of 2RE above the surface of the Earth, Mass of the Earth is 6xx10^24 kg, radius of the Earth = 6400 km and G = 6.67xx10^(-11) Nm^2 kg^(-2) .