The escape speed from earth's surface is `11kms^(-1)`. A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

The value of the escape velocity from the earth is v_e . If the radius of a planet is 4 times that of the earth and its density is 9 times the density of the earth, then the value of the escape velocity from that planet will be

Escape velocity for earth surface is 11 km/s. If the radius of any planet is two times the radius of the earth but average density is same that of earth, then the escape velocity at the planet will be ........

A planet has twice the radius but the mean density is 1/4 th as compared to earth. What is the ratio of escape velocity from earth to that from the planet

What will be the escape speed from a planet having radius thrice that of earth and the same mean density as that of the earth ? (Take v_(e)=11.2 km/s)

What will be the escape speed from a planet having radius thrice that of earth and the same mean density as that of the earth ? (Take v_(e)=11.2 km/s)

The escape velocity form the earth is 11 kms^(-1) the esacpe velocity from a planet having twice the radius and the same mean denisty as the earth would be

If the escape velocity on the earth.s surface is 11.2 "kms"^(-1) , its value on a planet having double the mass and double the radius that of the earth is