`9^(1+logx)-3^(1+logx)-210=0` where the base of log is `10`

Solve for x: a) (log_(10)(x-3))/(log_(10)(x^(2)-21)) = 1/2 b) log(log x)+log(logx^(3)-2)= 0, where base of log is 10. c) log_(x)2. log_(2x)2 = log_(4x)2 d) 5^(logx)+5x^(log5)=3(a gt 0), where base of log is 3. e) If 9^(1+logx)-3^(1+logx)-210=0 , where base of log is 3.

9^(1+log x)- 3^(1+log x) - 210 = 0 , where base of log is 3.

The value of x satisfying 5^logx-3^(logx-1)=3^(logx+1)-5^(logx - 1) , where the base of logarithm is 10 is not : 67 divisible by

int7^(x logx)(1+logx)dx=

(1)/(logx)-(1)/((log x)^(2))