Prove the identity; `(log)_a Ndot(log)_b N+(log)_b Ndot(log)_c N+(log)_c Ndot(log)_a N=((log)_a Ndot(log)_b Ndot(log)_c N)/((log)_(a b c)N)`

Prove that ((log)_(a)N)/((log)_(ab)N)=1+(log)_(a)b

prove identity log_(a)N*log_(b)N+log_(b)N*log_(c)N+log_(c)N log_(a)N=(log_(a)N*log_(b)N log_(c)N)/(log_(abc)N)

Statement 1 is True: Statement 2 is True; Statement 2 is a correct explanation for statement 1 Statement 1 is true, Statement 2 is true;2 Statement 2 not a correct explanation for statement 1. Statement 1 is true, statement 2 is false Statement 1 is false, statement 2 is true Statement I: If a=y^2, b=z^2, c=x^2, t h e n8(log)_a x^3dot(log)_b y^3dot(log)_c z^3=27 Statement II: (log)_b adot(log)_c b=(log)_c a , also (log)_b a=1/("log"_a b) a.A b. B c. C d. D

Compute the following a^(((log)_b((log)_a N))/((log)_b a))

Prove the following identities: (a) (log_(a) n)/(log_(ab) n) = 1+ log_(a) b" "(b) log_(ab) x = (log_(a) x log_(b) x)/(log_(a) x + log_(b) x) .

Prove that: log_(a)x=log_(b)x xx log_(c)b xx...xx log_(n)m xx log_(a)n

Compute a([(log_(b)(log_(b)N))/(log_(b)a)) Compute a((log_(b)(log_(b)N))/(log_(b)a))

((log)_(2)3)(log)_(3)4(log)_(4)5(log)_(n)(n+1)=10 Find n=?

log_(x rarr n)-log_(a)y=a,log_(a)y-log_(a)z=b,log_(a)z-log_(a)x=c