Solve for `x :5^(logx)+5x^(log5)=3(a >0);` where base of`log\ ` is a

Solve for x:5^(log x)+5x^(log5)=3(a>0)

Solve for x: a) (log_(10)(x-3))/(log_(10)(x^(2)-21)) = 1/2 b) log(log x)+log(logx^(3)-2)= 0, where base of log is 10. c) log_(x)2. log_(2x)2 = log_(4x)2 d) 5^(logx)+5x^(log5)=3(a gt 0), where base of log is 3. e) If 9^(1+logx)-3^(1+logx)-210=0 , where base of log is 3.

9^(1+log x)- 3^(1+log x) - 210 = 0 , where base of log is 3.

If 5^(log x)=50-x^(log5) then x=

9^(1+log x)-3^(1+log x)-210=0 where the base of log is 10

solve for x: logx + log5 = 2+ log 64

solve for x:2log_(10)x-log_(x)(0.01)=5

The value of X satisfying 5^(log x)-3^(log x-1)=3^(log x+1)-5^(log x-1) , (where the base of logarithm is 3 ),is

log(log x)+log(log x^(3)-2)=0; where base of log is 10 everywhere.