Show that the period of a simple pendium is given by `T=2pi sqrt((m)/(m),(1)/(g))` where m is the 'internial mass' and m is the 'gravitional mass' of the bob.

Find the dimensions of K in the relation T = 2pi sqrt((KI^2g)/(mG)) where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

A cylindrical log of wood of height h and area of cross-section A floasts in water. It is pressed and then released. Show that the log would execute S.H.M. with a time period T = 2pi sqrt(m//Arhog) where m is mass of the body and rho is density of the liquid.

The gravitational force F between two masses m_(1) and m_(2) separeted by a distance r is given by F = (Gm_(1)m_(2))/(r^(2)) Where G is the universal gravitational constant. What are the dimensions of G ?

If the inertial mass m_(1) of the bob of a simple pendulum of length 'l' is not equal to the gravitationalmass m_(g) , then its period is

If the inertial mass m_(1) of the bob of a simple pendulum of length 'l' is not equal to the gravitationalmass m_(g) , then its period is

What is the dimensional formula of (a) volume (b) density and (c ) universal gravitational constant 'G' . The gravitational force of attraction between two objects of masses m and m separated by a distance d is given by F = (G m_(1) m_(2))/(d^(2)) Where G is the universal gravitational constant.

Obtain an expression for the time period T of a simple pendulum. [The time period T depend upon (i) mass l of the bob (ii) length m of the pendulum and (iii) acceleration due to gravity g at the place where pendulum is suspended. Assume the constant k=2pi ]

If the speed v of a particle of mass m as function of time t is given by v=omegaAsin[(sqrt(k)/(m))t] , where A has dimension of length.

If the speed v of a particle of mass m as function of time t is given by v=omegaAsin[(sqrt(k)/(m))t] , where A has dimension of length.