" 22.सिद्ध करे: "[[1+a,1,1],[1,1+b,1],[1,1,1+c]]

Prove that : Det[[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+1/a+1/b+1/c)

Show that Determinant of [[1+a,1,1],[1,1+b,1],[1,1,1+c]] = abc (1+1/a+1/b+1/c)

Prove that the following. [[1+a,1,1],[1,1+b,1],[1,1,1+c]] = abc(1+1/a+/b+1/c)

Using properties of determinants show that abs[[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+1/a+1/b+1/c)

a^(−1) + b^(−1) + c^(−1) = 0 such that |[1+a,1,1,],[1,1+b,1,],[1,1,1+c,]| =△ then the value of △ is

a^(−1) + b^(−1) + c^(−1) = 0 such that |[1+a,1,1,],[1,1+b,1,],[1,1,1+c,]| =△ then the value of △ is

If a ,b and c are all non-zero and |[1+a,1, 1],[ 1,1+b,1],[1,1,1+c]|=0, then prove that 1/a+1/b+1/c+1=0

If a ,b and c are all non-zero and |[1+a,1, 1],[ 1,1+b,1],[1,1,1+c]|=0, then prove that 1/a+1/b+1/c+1=0

If a, b, c are all different from zero and Delta= |[1+a,1,1],[1,1+b,1],[1,1, 1+c]|=0 , then (1)/(a)+(1)/(b)+(1)/(c)=