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For N gt 1, then product 1/(log2N)* 1/(l...

For `N gt 1`, then product `1/(log_2N)* 1/(log_N8)* 1/(log_(32)N)*1/(log_N 128)` simplifies to (a) `3/7` (b) `3/(7ln2)` (c) `3/(5ln2)` (d) `5/(21)`

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If n>1, then prove that(1)/(log_(2)n)+(1)/(log_(3)n)+...+(1)/(log_(53)n)=(1)/(log_(53)n)

Prove that ((log)_(a)N)/((log)_(ab)N)=1+(log)_(a)b

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BANSAL-LOGARITHM-All Questions
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